2/(x^2-4)+(3x)/(x^2+5x+6)

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Solution for 2/(x^2-4)+(3x)/(x^2+5x+6) equation:


D( x )

x^2+5*x+6 = 0

x^2-4 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)

x = -2 or x = -3

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in (-oo:-3) U (-3:-2) U (-2:2) U (2:+oo)

2/(x^2-4)+(3*x)/(x^2+5*x+6) = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)

x = -2 or x = -3

(x+3)*(x+2) = 0

2/(x^2-4)+(3*x)/((x+3)*(x+2)) = 0

(2*(x+3)*(x+2))/((x^2-4)*(x+3)*(x+2))+(3*x*(x^2-4))/((x^2-4)*(x+3)*(x+2)) = 0

2*(x+3)*(x+2)+3*x*(x^2-4) = 0

3*x^3+2*x^2-2*x+12 = 0

3*x^3+2*x^2-2*x+12 = 0

3*x^3+2*x^2-2*x+12 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 12, -12 }

1

x = 1

3*x^3+2*x^2-2*x+12 = 15

1

-1

x = -1

3*x^3+2*x^2-2*x+12 = 13

-1

2

x = 2

3*x^3+2*x^2-2*x+12 = 40

2

-2

x = -2

3*x^3+2*x^2-2*x+12 = 0

-2

x+2

3*x^2-4*x+6

3*x^3+2*x^2-2*x+12

x+2

-3*x^3-6*x^2

12-4*x^2-2*x

4*x^2+8*x

6*x+12

-6*x-12

0

3*x^2-4*x+6 = 0

DELTA = (-4)^2-(3*4*6)

DELTA = -56

DELTA < 0

x in { -2}

x+2 = 0

(x+2)/((x^2-4)*(x+3)*(x+2)) = 0

(x+2)/((x^2-4)*(x+3)*(x+2)) = 0 // * (x^2-4)*(x+3)*(x+2)

x+2 = 0

x+2 = 0 // - 2

x = -2

x in { -2}

x belongs to the empty set

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